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pow:problem4s22 [2022/03/27 22:02] – created mazurpow:problem4s22 [2022/03/29 05:00] (current) mazur
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 +<box 85% round orange| Problem 4 (due on Monday, March 28) >
 +
 +The number $N=\frac{1}{2}ab(a^4+b^4)$, where $a,b$ are positive integers such that 
 +\[ a^4+b^4=1+ab(1+2+3+\ldots +(a+b)).\]
 +What is $N$?
 +
 +</box>
 +We have not received any solutions. The number $N=2022$.  For a complete solution see the following link {{:pow:2022sproblem4.pdf|Solution}}.
 +